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16. The Reckoning of a Recurrence

For positive integers nn, define the sequence c(n)c(n) by

c(1)=1,c(1)=1, c(2n)=c(n),c(2n)=c(n),

and

c(2n+1)=(−1)nc(n).c(2n+1)=(-1)^n c(n).

Find the value of

∑n=12027c(n)c(n+6).\sum_{n=1}^{2027} c(n)c(n+6).

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